Physics, asked by harsimranjit, 8 months ago

For a cell of e.m.f. 2 V, a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2 ohm resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is *<br /><br />2 points<br /><br />(a) 1 ohm<br />(b) 0.5 ohm<br />(c) 1.2 ohm<br />(d) 2.5ohm<br /><br />​

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Answered by ayushmanchatterjee40
0

Answer:

50 cm of the potentiometer wire. If the cell is shunted by a 2 ohm resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is *<br /><br />2 points<br /><br />(a) 1 ohm<br />(b) 0.5 ohm<br />(c) 1.2 ohm<br />(d) 2.5ohm<br /><br />

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