Physics, asked by arya2608, 1 year ago

For a certain organ pipe, three successive resonance frequencies are observed at 425, 595, and 765, hz respectively, taking the speed of sound in air to be 340 m/s the fundamental frequency of the pipe (in hz) is

Answers

Answered by abhi178
145
We don't know, which organ pipe is used for it , so, first of all we should take ratio of all three harmonics.
e.g., 425Hz : 595Hz : 765 Hz
⇒5 × 85 Hz : 7 × 85Hz : 9 × 85 Hz
⇒ (2 × 2 + 1) 85Hz : (2 × 3 + 1) 85Hz : (2 × 4 + 1) 85Hz
what you saw, each the successive harmonics is an odd number.
This is possible only when organ pipe is closed .
And 85 is common for all harmonics , so fundamental frequency is 85Hz
Similar questions