Question

for a complete oxidation of 4 litres of CO at NTP , the required volume of O2 at NTP is

Answer 1

According to ideal gas law, the volume occupied by 1 mole of a gas at NTP or STP is 22.4 liters.

Find moles of 4 liters of CO:

If 22.4 liters of CO is 1 mole
Then 4 liters of CO = 1 × 4/22.4
                               =  0.1786 moles

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The equation for the reaction of the oxidation of CO is :

2 CO(g) + O₂(g) = 2 CO₂(g)

The mole ratio between CO and O₂ in the equation is 2 : 1

The moles of 4L CO is 0.1786 moles
mole ratio is 2:1...that means we need 0.1786/2 = 0.08923 moles of oxygen to react with CO

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Find volume of oxygen using this calculated mole of 0.0893. 

Ideal gas law 1 mole = 22.4 liters

If 1 mole = 22.4 liters 
Then 0.0893 moles = 0.0893 × 22.4/1

                               = 2 liters of oxygen.