Question

For a concave mirror of focal length 10cm magnificent of a real image is 3.The real image is​

Answer 1

Answer:

the image height is 40cm and beyond the centre of curvature.

Explanation:

the linear magnification is 3 .

let the object height is X so the image will be 3X.

the focal length is 10cm

putting the values in 1/v+1/u=1/f we get

1/3X+1/X=1/10

or, 4/3X=1/10

or, X=40/3

the object height is 40/3 cm.

so, the image height is 40/3*3=40cm