Business Studies, asked by samdubeybest, 3 months ago

For a continuous data distribution, 10-20 with frequency 3, 20-30 with frequency 5, 30-40 with frequency 7and 40-50 with frequency 1, the value of Q_3 is

Answers

Answered by pulakmath007
3

SOLUTION

GIVEN

For a continuous data distribution, 10-20 with frequency 3, 20-30 with frequency 5, 30-40 with frequency 7and 40-50 with frequency 1

TO DETERMINE

 \sf{The  \: value \:  of  \:  \: Q_3}

EVALUATION

Here it is given that For a continuous data distribution, 10-20 with frequency 3, 20-30 with frequency 5, 30-40 with frequency 7and 40-50 with frequency 1

We draw the frequency table as below

\begin{gathered} \begin{array}{|c|c| c| } \sf{Class \: Interval} & \sf{Frequency}& \sf{Cumulative \: freq.} \\ 10 - 20 & 3 & 3  \\20 - 30 & 5 & 8  \\30 - 40 & 7 & 15 \\40 - 50 & 1 & 16  \end{array}\end{gathered}

Now N = 16

Therefore

\displaystyle\sf{ \frac{3N}{4}  = 12}

Now cumulative frequency just greater than 12 is 15

So upper quartile class is 30 - 40

Thus we get

l = 30 , f = 7 , h = 10 , F = 8

\displaystyle\sf{Q_3 = l +  \frac{ \frac{3N}{4} - F }{f}  \times h}

\displaystyle\sf{ \implies \: Q_3 = 30+  \frac{ 12 - 8 }{7}  \times 10}

\displaystyle\sf{ \implies \: Q_3 = 30+  \frac{ 40 }{7} }

\displaystyle\sf{ \implies \: Q_3 = 30+ 5.7 }

\displaystyle\sf{ \implies \: Q_3 = 35.7 }

FINAL ANSWER

 \boxed{ \:  \: \displaystyle\sf{  \: Q_3 = 35.7 } \:  \: }

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