Math, asked by Sayedibhrahim1298, 1 year ago

For a couple if the present age of husband is 2 years more than wife,whose present is 36 years less than 10 times of 10 years .What will be the ratio of their ages?

Answers

Answered by MonsoonMamta
0
Wife=64
Husband=64+2
=66
Answered by Tasmiyak
0
{10(10)-36}/{10(10)-36+2}
(100-36)/(100-34)
64/66
32:33
hope it helps
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