Math, asked by menemebe7739, 1 year ago

For a couple if the present age of husband is 2 years more than wife,whose present is 36 years less than 10 times of 10 years .What will be the ratio of their ages?

Answers

Answered by santy2
1

Answer:


33 : 32


Step-by-step explanation:


Age of the wife :


(10 × 10) - 36 = 64 years


Husband = 64 + 2 = 66 years


The ratio of their ages :


Husband : wife


66 : 64


33 : 32


Answer = 33 :32

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