Question

for a diatomic gas Cv= 5R/2 then gamma for this gas

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Answer 1

Answer:

The degrees of freedom is 3 for monatomic gas and 5 for diatomic gas (3 translational + 2 rotational). The internal energy of an ideal gas at absolute temperature T is given by U=fRT/2 U = f R T / 2 .

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Specific Heats (Cv and Cp for Monatomic and Diatomic Gases)

Monatomic Diatomic

Cp 5R/2 7R/2

γ 1.67 1.40

Answer 2

Given:

For a diatomic gas Cv= 5R/2.

To find:

Value of $\gamma$ for the gas?

Calculation:

$C_{V}= \dfrac{5R}{2}$

Now, we can say:

$C_{P} = C_{V} + R$

$\implies C_{P} = \dfrac{5R}{2} + R$

$\implies C_{P} = \dfrac{7R}{2}$

So, value for Gamma :

$\gamma = \dfrac{C_{P}}{C_{V}}$

$\implies \gamma = \dfrac{ \dfrac{7R}{2} }{ \dfrac{5R}{2} }$

$\implies \gamma = \dfrac{ 7 }{5}$

$\implies \gamma = 1.4$

So, value of Gamma is 1.4 .