For a dipole q=2×10-6 and 2a=0.002 calculate the maximum torque acting on dipole if e=5×10-5
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please refer the attachment.
Hope this helps you quickly
Hope this helps you quickly
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Dear Student,
◆ Answer -
τ = 2×10^-13 Nm
● Explanation -
# Given -
q = 2×10^-6 C
2a = 0.002 m
E = 5×10^-5 N/C
# Solution -
Maximum torque acting on dipole is given by -
τ = P × E
τ = q×2a × E
τ = 2×10^-6 × 0.002 × 5×10^-5
τ = 2×10^-13 Nm
Hence, maximum torque acting on the dipole is 2×10^-13 Nm.
Thanks dear. Hope this helps you...
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