Question

for a distribution ₹810 has to be divided among first , second and third prize in the ratio 4:3:2 . find the share of each winner 11​

Answer 1

let ratio's be X

so 4x:3x:2x

money to be distributed = 810

so.

4x+3x+2x= 810

9x= 810

X= 90

so money to be distributed

4x= 90*4= 360

3x= 90*3= 270

2x= 90*2= 180

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Answer 2

Answer:

money given for 1st winner = 360

money given for 2nd winner = 270

money given for3rd winner = 180

Step-by-step explanation:

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