for a first order reaction a--->b if volume of reaction vessel is reduced to 1/3 then rate of reaction would become
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The volume in the reaction depends inversely upon the rate of the reaction hence if the volume increases then the rate of the reaction will decrease.
We know this by the formulae rate of reaction r = k[A] where A is the concentration of the reaction which is nothing but moles per unit volume thus rate is inversely proportional to volume.
Hence, in the given question volume is reduces by 1/3 so rate of the reaction will increase.
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