Question

For a first order reaction rate constant is 6.93*10-3 per sec then the half life is

Answer 1

Half life of a first order reaction can be calculated using the formula:

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}$, is the half life time of a reaction

k, is the rate constant

Here,  

Where, k=6.93×10⁻³  

So putting the value of rate constant in the above equation  

$t_{\frac{1}{2}}=\frac{0.693}{6.93\times 10^{-3}}$

$t_{\frac{1}{2}}=100 sec$

$t_{\frac{1}{2}}=1.6 min$