Math, asked by gurtejramgarhia2232, 1 year ago

Solve this problem cos (a+b)cosc-cos (b+c)cosa=sinbsin (c-a)

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Answered by Anonymous

= (cosAcosB - sinAsinB)cosC - (cosBcosC - sinBsinC)cosA= cosAcosBcosC - sinAsinBcisC - cosAcosBcosC + sinBsinCcosA= sinBsinCcosA - sinBsinAcosC= sinB(sinCcosA - cosCsinA)= sinBsin (C- A)......PLEASE FOLLOW ME.....

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