Question

For a first order reaction, the value of rate constant
for the reaction is?
A(gas) ----> 2B(gas)+ C (solid)
​

Answer 1

Answer:

A first-order reaction has a rate proportional to the concentration of one reactant. First-order rate constants have units of sec-1. In other words, a first-order reaction has a rate law in which the sum of the exponents is equal to 1.

Answer 2

The given question is incomplete. The complete question is as follows.

For a first order reaction, value of rate law is $2.0 \times 10^{-3}$ and [A] = 0.1, find the value of rate constant  for the reaction

$A(g) \rightarrow 2B(g) + C(s)$ ?

Explanation:

Rate constant for a first order reaction is defined as an expression of rate of a reaction where the concentration of each of the reactants is equal to unity.

For example, $A(g) \rightarrow 2B(g) + C(s)$

Hence, rate constant for this first order reaction is as follows.

         Rate law = k[A]

where,   k = rate constant

Putting the given values into the above formula we will find the value of rate constant as follows.

              Rate law = k[A]

     $2.0 \times 10^{-3} = k \times 0.1$

              k = $2 \times 10^{-4}$

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