For a freely falling body from a height ‘H’, the time taken to reach ground is ___
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t =√2H/√9.8
Explanation:
We know, displacement is 's' . So,
s = ut + 1/2at²
Here,
Initial velocity,u = 0 ,. height,s = H,. acceleration due to gravity,a = g(9.8m/s)
So,
- H = 0t + 1/2gt²
- H = 1/2gt²
- t² = 2H/9.8
- t = √2H/√9.8
Hope it helps
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