Question

For a freely falling body, the ratio of distances
travelled in 1 second, 2 seconds, 3 seconds,
=1:4:9:16....
For a freely falling body, the ratio of distances
travelled in successive seconds = 1:3:5:9...
A freely falling body passes through two points
A and B in time intervals oft and t from the
start, then the distance between the two points​

Answer 1

Answer:

2x +4(2x+7)=3(2x+4)

2x + 8x + 28=6x + 12

10x + 28 = 6x +12

4x + 28= 12

4x=-16

x=-4