Question

(x-√3y)^2 answer please​

Answer 1

Answer:

${(x - \sqrt{3} y)}^{2} \\ = {x}^{2} + {( \sqrt{3} y)}^{2} - 2 \times x \times \sqrt{3} y \\ = {x}^{2} + 3 {y}^{2} - 2 \sqrt{3} xy$