Math, asked by dilippatani14gmail, 1 year ago

for a given A.P. 5,10,15,20,...,200, what is the number of terms

Answers

Answered by VarshaD
14
an=a+(n-1)d
200=5+(n-1)5
200-5=(n-1)5
195/5=(n-1)
39=n-1
n=40.

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Answered by Vanshsharma420
10


a=5
d= 10-5=5

L= an
an= a + (n-1)d
200=5 + (n-1)5
200-5= (n-1)5
195÷5=(n-1)
39+1=n
40=n

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