Question

In 3 fractions when the largest
fraction is divided by smallest fraction
the result 5/4 is greater than the middle fraction by 1/2, if sum of the three fraction is 2(3/12), what will be the difference between largest and smallest fraction.?
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Answer 1

Step-by-step explanation:

Let largest fraction x, middle y,smallest z

As per question x/z=5/4

So,x=5z/4

Given y=5/4-1/2=3/4

also given x+y+z=27/12=9/4

So,5z/4+3/4+z=9/4

5z/4+z=9/4-3/4=6/4

or 9z/4=6/4

or9z=6

or,z=6/9=2/3

Since x=5z/4=5/4×2/3=5/6

So,x-z=5/6-2/3=1/6 Answer

Answer 2

Answer:

1/6

Step-by-step explanation:

Let the largest fraction be x, the middle fraction be y and smallest fraction be z.

Given:- $\frac{x}{z} = \frac{5}{4}$ and $\frac{5}{4} = \frac{1}{2} +y$ and $x + y+z = 2\frac{3}{12}$

To Find:- Difference between largest and smallest fraction.

Solution:-

As, $\frac{5}{4} = \frac{1}{2} +y$

⇒ $y = \frac{5}{4} -\frac{1}{2}$

⇒ $y = \frac{5-2}{4}$

⇒ $y = \frac{3}{4}$      

As, $\frac{x}{z} = \frac{5}{4}$

⇒ $x = \frac{5z}{4}$

Putting $y = \frac{3}{4}$ and $x = \frac{5z}{4}$ in equation $x + y+z = 2\frac{3}{12}$, we get

⇒ $\frac{5z}{4} +\frac{3}{4} +z = \frac{27}{12}$

⇒ $\frac{5z+3+4z}{4} = \frac{27}{12}$

⇒ $9z + 3 = \frac{27}{3}$

⇒ $9z+3 = 9$

⇒ $z = \frac{9-3}{9}$

⇒ $z = \frac{2}{3}$

So, $x = \frac{5}{4} * \frac{2}{3}$  ⇒ $x = \frac{5}{6}$.

Hence, the difference between largest and smallest fraction becomes $\frac{5}{6} -\frac{2}{3}$ = $\frac{1}{6}$

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