for a given arithmetic progression, T10 = 41 and S10= 320. find TN and SN for this arithmetic progression
Answers
Answered by
12
tn = 21 + 2n
sn = 22n + n^2
sn = 22n + n^2
Attachments:
Answered by
1
Step-by-step explanation:
hope you got your answer please mark me as brainliest
Attachments:
Similar questions