Math, asked by saiyamsanghvi, 1 year ago

for a given arithmetic progression, T10 = 41 and S10= 320. find TN and SN for this arithmetic progression

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Answered by Ashish02

12

tn = 21 + 2n

sn = 22n + n^2

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Answered by rajpurohitmohit577

1

Step-by-step explanation:

hope you got your answer please mark me as brainliest

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