For a given two-digit positive integer, the tens digit is 3 more than the units digit. The sum of the digits is 11. What is the integer
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Step-by-step explanation:
Let the unit digit be a and tens digit be b. Then,
Sum of digit = a+b = 11 , b = 11-a
A/C,
By substituting the value of b in this equation -
● b = 3+a
11-a = 3+a
11-3 = a+a
8 = 2a
8/2 = a
4 = a
By substituting the value of a in this equation -
● b = 11-a
b = 11 - 4
b = 7
Original no = 10×7 + 4
= 74
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