For a GP if S3 = 16 , S6=144
find the first term and the common
ratio of the GP.
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Given : S₃ = 16 and S₆ = 144
To Find : the first term and the common ratio
Solution:
S₃ = 6 and S₆ = 144
Sₙ = a(rⁿ - 1)/(r - 1)
a = first term
r = common ratio
n = number of terms
S₃ = a(r³ - 1)/(r - 1) = 16
S₆ = a(r⁶ - 1)/(r - 1) = 144
S₆ / S₃ = 144/16 = 9
=> S₆ / S₃ = {a(r⁶ - 1)/(r - 1)} / {a(r³ - 1)/(r - 1)}
= (r⁶ - 1) / (r³ - 1)
= (r³+ 1)
r³+ 1 = 9
=> r³ = 8
=> r = 2
S₃ = a(r³ - 1)/(r - 1) = 16
=> a(2³ - 1)/(2 - 1) = 16
=> a ( 7) = 16
=> a = 16/7
First term = 16/7
and common ratio =2
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