Math, asked by krishsharma76097609, 1 month ago

The value of 5 tan2A-5 sec2A+1 is:​

Answers

Answered by BipashaDutta
0

Answer:

5tan

2

θ−5sec

2

θ

⇒5(tan

2

θ−sec

2

θ)=5(−1)=−5 [∵1tan

2

θ=sec

2

θ] Hence, the answer is -5.

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