Question

for a GP t1=a and t 5=1/a, where a>0 then obtain its third term​

Answer 1

Answer:

1

Step-by-step explanation:

here t1=a,t5=1/a so common ratio is 1/√a

So, t3=a×1/√a×1/√a =1

Answer 2

Answer:

1

Step-by-step explanation: