Question

For a hydraulic device, a piston has a cross-sectional area of 30 square centimetres moving an in-compressible liquid with a force of 60 N. The other end of the hydraulic pipe is attached to a 2nd piston with a 60 square centimetre cross-sectional area. Determine the force on the second piston

Answer 1

Answer:

Given

F1 = 60 N

A1 = 30 square centimeters

A2 = 60 square centimeters

Insert the given values to calculate the force on the second piston:

F2 = A2 x F1/A1

F = 60 x 60 / 30

F = 120 N

Explanation:

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Answer 2

Answer:

F1 = 60 N

A1 = 30 square centimeters

A2 = 60 square centimeters

Insert the given values to calculate the force on the second piston:

F2 = A2 x F1/A1

F = 60 x 60 / 30

F = 120 N