for a journey A to B a boy travels with 5kmph,10kmph, 15kmph for equal time intervals and while moving from B to A he moves with speeds 5kmph,10kmph,15kmph for equal distances. find the average speed of the boy.
answer is 9kmph
want the solution
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Answer:
Required average speed,
=(3×40×30×15)/(40×30)+(40×15)+(30×15)
=24km/hr
Alternatively
Time taken to traveled 1/3
distance of journey with speed 40 kmph,
=1/3/40=1/120
Time taken to traveled 1/3
distance of journey with speed 30 kmph,
=1/3/30=1/90
Time taken to traveled 1/3
distance of journey with speed 15 kmph,
=1/3/15=1/45Total time taken=1/120+1/90+1/45=45/1080Average speed=Total distance traveled/Total time taken=1/45/1080=24kmph
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