Question

for a laminar flow in a pipe if the centre line velocity is 0.1 m/sec the average velocity is what​

Answer 1

Answer:Vmax is at centre

we know,

Vmax/vavg=

Vmax= .1, Therefore, Vavg=1/

Step-by-step explanation:

Answer 2

Answer: It is generally not possible to determine the average velocity.

Step-by-step explanation:

For laminar flow in a pipe, the average velocity is typically lower than the centerline velocity. In laminar flow, the fluid moves in parallel layers with no turbulence or mixing between layers. As a result, the fluid velocity is highest at the center of the pipe and decreases towards the walls, creating a parabolic velocity profile.

To determine the average velocity, we can integrate the velocity profile over the cross-sectional area of the pipe and divide by the cross-sectional area. The equation for average velocity (V_avg) is given by:

V_avg = (2/A) * ∫_0^R v(r) * r * dr

Where A is the cross-sectional area of the pipe, R is the radius of the pipe, and v(r) is the velocity at a distance r from the centerline. In the case of laminar flow in a pipe, the velocity profile can be modeled as a parabolic function with the centerline velocity (V_cl) as the maximum value.

So, if the centerline velocity is 0.1 m/sec, the average velocity would be lower than 0.1 m/sec. The exact value of the average velocity would depend on the specific geometry of the pipe, including its diameter and the fluid properties, such as its density and viscosity. It is generally not possible to determine the average velocity with a single value such as 0.1 m/sec without more information about the specific conditions of the flow.

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