for a man who walks 720m at a uniform speed of 2m/s,then runs at a uniform speed of 4m/s for 5 minutes and then again walks at a speed of 1m/s for 3 minited.What is the average speed
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7
Answer:
Explanation:
Average speed = total distance
total time
The man walks 720 m at a uniform speed of 2 m/s.
time taken= 720/2 = 360 seconds
Then the man walks for 5 min. at 4 m/s, hence the total distance travelled= speed x time
= 4 x 5 x 60 (time in seconds)
= 1200 m
Then the man walks for 3 min. at 1 m/s, hence the total distance travelled= speed x time
= 1 x 3 x 60 (time in seconds)
= 180 m
total distance travelled = 720 + 1200 +180 m
= 2100 m
total time taken = 360 + 5 x 60 +3 x 60
= 360 + 300 + 180
= 840 seconds
hence average speed= 2100/840
= 2.5 m/s
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Answered by
5
Explanation:
Average speed = total distance
total time
The man walks 720 m at a uniform speed of 2 m/s.
time taken= 720/2 = 360 seconds
Then the man walks for 5 min. at 4 m/s, hence the total distance travelled= speed x time
= 4 x 5 x 60 (time in seconds)
= 1200 m
Then the man walks for 3 min. at 1 m/s, hence the total distance travelled= speed x time
= 1 x 3 x 60 (time in seconds)
= 180 m
total distance travelled = 720 + 1200 +180 m
= 2100 m
total time taken = 360 + 5 x 60 +3 x 60
= 360 + 300 + 180
= 840 seconds
hence average speed= 2100/840
= 2.5 m/s
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