For a manufacturer A, the list price of an article is rupees 9000, which he sales to dealer B at a some discounted price . Further, the dealer B sales the same article to the customer at it's list price. If the rate of the GST is 18% and dealer B paid the SGST rupees 160 , find the amount ( including GST)
paid by dealer B
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Answer: Rs 8522.22
For B, SGST payable will be Output SGST- Input SGST.
OUTPUT SGST= 9% of 9000 (as B is selling at list price)
let the price at which B buys = x
Therefore, INPUT SGST= 9% of x
Hence, 9%of 9000 - 9% of x= 160
On solving, we get x= Rs 7222.22
Therefore, amount payable by B is 7222.22+ 18% of 7222.22 =
7222.22+ 1300=
Rs 8522.22
Hope this helps.
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