Question

For a mass of 2 kg, the velocity-time
graph is given here. Find the force experienced
by the mass in regions OA, AB and BC.
​

Answer 1

Answer:

Force for OA = 4 N.

Force for AB = 0 N.

Force for BC = -4 N...

Explanation:

...

For OA acceleration = 2 m/s² {change in velocity / time}...

so force = ma

F = 2×2= 4 N.

F = 4 N...

For AB there is no change in velocity so the work done = zero.

For BC acceleration 0-20/10 { (velocity final- velocity initial)/time}

acceleration = -20/10

acceleration = -2 m/s²

Force = ma = 2×-2= -4N

Force = -4N...