Question

for a monoatomic gas cv 3R/2 therefore gamma y for this gas is ​

Answer 1

Answer:

$\huge{ \green{ \gamma = \frac{5}{3} }}$

Explanation:

We know

$C_p - C_v = R \\ \\C_p - R = \frac{3R}{2} \\ \\ C_p = R + \frac{3R}{2} = \frac{5R}{2}$

So

$\gamma = \frac{C_p }{C_v} = \frac{5}{3}$