Question

For a moving body, displacement in) x=10t+ 20 t^2 where t is in second find its velocity and acceleration

Answer 1

Answer:

$x = 10t + 20 {t}^{2}$

$∆v = \displaystyle\frac{d}{d t } \left(10t+20t ^ { 2 } \right)$

$∆v = 40t + 10 \: ms^{ - 1}$

$\displaystyle∆a= \displaystyle\frac{dv}{dt} = \displaystyle\frac{d}{d t } \left(40t+10 \right)$

$\displaystyle∆a = 40 \: ms^{ - 2}$