Question

For a particle moving along a straight line, the vt curve is as given below (a) Find the displacement of the particle in 4 s (b) Find the acceleration of the particle in 4 s ​

Answer 1

Answer:

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Explanation:

If y=x(t) be the position of a particle with respect time t, then the average velocity of the particle from t=a to t=b is given by, vavg=b−ax(b)−x(a)

Here, a=2sec and b=4sec ;

x(a)=2,x(b)=0

So, vavg=4−20−2=−1

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