For a particle moving along x-axis, position (x in metre) and time (t in seconds) are related by x =t2+4t+8momentum of the particle of mass 2 kg at t = 3 seconds is ________kg ms−1
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Answer:
x=t
2
−4t+6
So, the change in velocity is:
dt
dx
=2t−4
Since velocity is changing,
At t=0,x
1
=6
At t=2,x
2
=2
So the magnitude of the distance traveled is:
6−2=4m
At t=3,x
3
=3
So distance traveled from t=2s to t=3s
x
3
−x
2
=3−2=1m
Thus the total distance is:
4+1=5m
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