Question

For a particle moving along x-axis, velocity-time graph is as shown in figure. Find the distance travelled
and displacement of the particle? Also find the average velocity of the particle in intervel 0 to 5 second.
GRAPH IN ATTACHMENT.
Best answer will be marked as BRAINLIEST
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Answer 1

Answer:

distance =1/2×2×4 +1×4 +1/2×2×2=4+4+2=10m

displacement =+(1/2×2×4)+(1×4)-(1/2×2×2)

=+4+4-2=+6m

Average velocity =+6m/5s

=1.2m/s

Answer 2

Distance= 10m

Displacement = 6m

Average Velocity = 1.2m/s

Explanation:

The distance travelled by the particles is,

$=\frac{1}{2}\times2\times4+4\times(3-2)+\frac{1}{2}\times2\times(5-3)$

$=4+4\times1+1\times2$

$=4+4+2\\=10\ m$

The displacement travelled by the particles is,

$=\frac{1}{2}\times2\times4+4\times(3-2)-\frac{1}{2}\times2\times(5-3)$

$=4+4\times1-1\times2$

$=4+4-2\\=6\ m$

Average velocity $v$,

$v=\frac{Displacement}{Time}$

$v=\frac{6}{5}$

$v=1.2\ ms^{-1}$

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