For a positive integer 'p', p³ may not be greater than p². State TRUE or FALSE. plz help me!.....
Answers
Answered by
3
HEY MATE HERE IS UR ANSWER
THIS IS
TRUE FOR SURE AS IN POSITIVE INTEGERS WHICH 0 - INFINITE
THERE FOR THE NUMBER 1 CAN ALSO BE POSITIVE INTEGER .
BUT 1^2 = 1
1^3 = 1
THEREFORE
1^3= 1^2
THERE FOR HEAR THE NUMBER CUBE IS NOT GREATER THAN SQUARE.
HOPE IT'S HELPFUL IF YES PLEASE MARK AS BRAINLIEST!!!
@NIPUN
THIS IS
TRUE FOR SURE AS IN POSITIVE INTEGERS WHICH 0 - INFINITE
THERE FOR THE NUMBER 1 CAN ALSO BE POSITIVE INTEGER .
BUT 1^2 = 1
1^3 = 1
THEREFORE
1^3= 1^2
THERE FOR HEAR THE NUMBER CUBE IS NOT GREATER THAN SQUARE.
HOPE IT'S HELPFUL IF YES PLEASE MARK AS BRAINLIEST!!!
@NIPUN
420kiikiichan15905:
thank you!!...
Answered by
2
True
as it says May not
it basically says that there are few cases where the p³ < P2 ( not all )
for ex 6³>6²
but 0.5³<0.5² ( you can do the math )
positive just means greater than 0 , not greater than 1
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