Question

for a prism of angle of 60^° , angle of incidence is 48^°.find its minimum angle of deviation.​

Answer 1

Explanation:

Angle of minimum deviation

A - Angle of prism = 60

Since u want minimum deviation ,

Angle of incidence ( i )= Angle of emergence ( e ) = 48

i + e = A +

= 2i - A

= 2(48) - 60

= 96 - 60

= 36