Question

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 ms?2) [EAMCET (Med.) 2000]
A) 5 : 4 B) 5 : 2 C) 5 : 1 D) 10 : 1

Answer 1

5:2
.................

Answer 2

H=u^2 sin^2 theta/2g.................1

T^2= 4u^2 sin^2 theta/g^2..................2

H/T^2= g/4.....(after cancellation)

=10/4......(putting g=10)

=5/2

Here is your answer.