Question

For a reaction:
3A → products
It is found that the
rate
of
reaction
doubles when the
concentration of A is
increased by four
times. What is the
order
of
the
reaction?​

Answer 1

Answer:

1/2

Explanation:

Rate = k [Reactant]^n

if [Reactant] = a ; rate = r1

if [Reactant] = 4a ; rate = 2r1

r1 = k [4a]^n

2r1 =k [4a]^n

1/2 = [1/4]^n

n = 1/2