For a reaction A+2B - C, How many moles of C will be formed by starting the reaction with moles of A and 8 moles of B?
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Heya
I guess it is 5 miles of A and 8 moles of B
Reaction : A+2B --> C
1 mole + 2 moles of B => 1 mole of C
When 1 mole of A reacts with 1×2=2 moles of B, then we get 1 mole of C
When there are 5 moles of A, 5×2=10 moles of B is required to get 5 moles of C
But here, we have just 8 moles of B.
A is in excess and B is called the limiting agent.
The amount of C formed will depend only on amount of B available as A is in excess.
2moles of B -> 1 mole of C
8 moles of B -> 8×1/2= 4moles of C
Hope it helso
I guess it is 5 miles of A and 8 moles of B
Reaction : A+2B --> C
1 mole + 2 moles of B => 1 mole of C
When 1 mole of A reacts with 1×2=2 moles of B, then we get 1 mole of C
When there are 5 moles of A, 5×2=10 moles of B is required to get 5 moles of C
But here, we have just 8 moles of B.
A is in excess and B is called the limiting agent.
The amount of C formed will depend only on amount of B available as A is in excess.
2moles of B -> 1 mole of C
8 moles of B -> 8×1/2= 4moles of C
Hope it helso
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