Question

For a reaction,
A+B -- 2C+2D,Kp=1.2×10^3 kPa at 450k. Calculate the value of Kc in mol/l.

Answer 1

Kp is equilibrium constants and it could be defined as the partial pressure of a gasoline inner a closed system.

For the reaction,

A+B---2C+2D

Given, Kp=1.2×10^3 kPa

and T=450k

we know that, Kp=Kc(RT)Δn

For the given reaction, Δn=n₂-n₁=4-2=2

and the value of R=8.314 J/molK

putting the value in the above equation,

1.2×10^3 kPa=Kc(8.314 J/molK×450k)×2

Kc= 1.6×10^-1 mol/l