Question

for a reaction A+B 2C+2D ,kp=1.2×10th the power 3 kpa at 450k. calculate the value of ke in mol/lit​

Answer 1

Kp and Kc are the gas constant of a gaseous mixture. Where Kp is the molar concentrations and Kc is the partial pressure of a gas inside a closed system.

For the given reaction,

A+B---2C+2D

given,

Kp=1.2×10³ k Pa

Kp=1.2×10³×10³Pa

    =1.2×10⁶Pa=1.2×10⁶×9.869×10⁻⁶atm

    =11.8atm

and the temperature,T= 450 k

R=0.08206 L atm/mol k

Here, Δn=n₂-n₁=4-2=2

Relation between Kp and Kc is,

Kp=Kc(RT)Δn

⇒11.8=Kc(0.08206×450)²

⇒11.8=Kc(86.927)²

⇒Kc≅0.009mol/L