Question

For a reaction at equilibrium A(g)+B(g)=C(g) having total pressure 5 atm, if the percentage dissociation is 40%, what was the initial pressure?
(1) 3.57 atm
(2) 4.57 atm
(3) 5.57 atm
(4) 6.57 atm​

Answer 1

For a reaction at equilibrium A(g)+B(g)=C(g) having total pressure 5 atm, if the percentage dissociation is 40%, what was the initial pressure?

(1) 3.57 atm

(2) 4.57 atm

(3) 5.57 atm✔️✔️✔️

(4) 6.57 atm

Answer 2

The given question is incomplete. The given question is:

For a reaction at equilibrium A(g)=B(g)+C(g) having total pressure 5 atm, if the percentage dissociation is 40%, what was the initial pressure?

(1) 3.57 atm

(2) 4.57 atm

(3) 5.57 atm

(4) 6.57 atm​

The initial pressure was 3.57 atm.

Explanation:

The balanced chemical reaction is:

         $A(g)\rightarrow B(g)+C(g)$

Initial pressure      x            0       0

At eqm.            (x-0.4x)    (0.4x)   (0.4x)

As we are given that:

Total pressure = 5 atm

(x-0.4x)+(0.4x)+(0.4x)= 5 atm

That means,

$1.4\times x= 5$

x= 3.57atm

Thus the initial pressure was 3.57 atm

Learn more about equilibrium constant:

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