Question

for a reaction,kt+10/kt=x.when temperature is increased from 10℃ to 100℃ rate constant increased by factor 512.then value of x is

Answer 1

value of x will be between 2 to 3.this value shall always reamain constant whenever the temperature us increased by 10.

Answer 2

2 is the proper answer.

Explanation:

• A traditionally beneficial generalization supported through Arrhenius' equation is that, for plenty of common chemical reactions at room temperature, the response price doubles for each 10 degree Celsius(kelvin) growth in temperature.
• right here k​​​​​​t+10/ kt =x.
• 10-degree rise so the solution is 2.
• 10 to 100 this is 100-10 =90.
• this is nine times 10 degrees so 2⁹=512.

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