Question

For a reaction, N2(g) + 3H2(g) gives 2NH3(g); indentify dihyodrogen (H) as a limiting reagent in the following(a)56 g of NE + 10 g of H2 (b) 35 g of N2 + 8g of H2 (c) 28 g of N2 + 6g of H2 (d) 14 g of N2 + 4 g of H2​

Answer 1

Answer:

(a) 56g of N

2

+10g of H

2

Explanation:

N

2

(g)+3H

2

(g)→2NH

3

(g)

In the given reaction, 1 mol of N

2

reequires 3 moles of H

2

for the formation fo ammonia.

Thus if the number of moles of N

2

and H

2

should be in ratio 1:3.

We know,

n=

molecular weight

weight

Thus in option C 56g of N

2

means 2 moles of N

2

and 10g of H

2

means 5 moles of H

2

.

Thus here H

2

acts as limiting reagent.