Question

The L.C.M.of two numbers is 33 and their product is 33 find their H.C.F.

Answer 1

Answer:

Factoring of 33: 3 and 11

3 x 1 = 3

3 x 2 = 6

3 x 3 = 9

3 x 4 = 12

3 x 5 = 15

3 x 6 = 18

3 x 7 = 21

3 x 8 = 24

3 x 9 = 27

3 x 10 = 30

The sum of 33 has to be composed of an odd and even number.

Then:

3 + 30 = 33 - 3 and 30 have their HCF as 3

6 + 27 = 33 - 6 and 27 have their HCF as 3

9 + 24 = 33 - 9 and 24 have their HCF as 3

12 + 21 = 33 - 12 and 21 have their HCF as 3

15 + 18 = 33 - 15 and 18 have their HCF as 3

The maximum possible is 3.

With the factor 11, then we have: 11 + 22 = 33

11 x 1 = 11

11 x 2 = 22

Step-by-step explanation:

Hope it hepls u

Answer 2

Answer:

The HCF of the two numbers = 1

Step-by-step explanation:

Given

The LCM of two numbers = 33

The product of two numbers = 33

To find,

The HCF of the two numbers

Recall the formula

LCM × HCF  = Product of two numbers ------------------(A)

Solution

Let HCF be x

Since, LCM of the two numbers is 33

LCM × HCF = 33x

Since product of the two numbers = 33, from (1) we get

33x = 33

x = $\frac{33}{33}$ = 1

The HCF of the two numbers = 1

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