Math, asked by chimchartorcoal, 5 days ago

for a real function , f(x)=6x^3-5^x+15 find f(0) ​

Answers

Answered by shivammauryahrc
2

Answer:

14

Step-by-step explanation:

given function is:

f(x)=6x^3-5^x+15

=> f(0)=6*0^3-5^0+15

=> f(0) = 6*0 - 1 + 15

=> f(0) = -1 + 15

=> f(0) = 14

Thank you!

Similar questions