Question

For a rectangular playground, its length is 80 m and its breadth is 60m, find [3] The distance moved by a boy to make one complete round of the field and The distance moved by the same boy to make ten rounds of this field.

Answer 1

280 is the correct answer

Answer 2

The distance moved by a boy to make one complete round of the field and the distance moved by the same boy to make ten rounds of this field is 280m and 2800m respectively.

Given:-

Length of the playground = 80m

Breadth of the playground = 60m

To Find:-

The distance moved by a boy to make one complete round of the field and the distance moved by the same boy to make ten rounds of this field.

Solution:-

We can easily find out the distance moved by a boy to make one complete round of the field and the distance moved by the same boy to make ten rounds of this field by using these simple steps.

As

Length of the playground (l) = 80m

Breadth of the playground (b) = 60m

The perimeter of the rectangular field (p) =?

Here, the playground is in the shape of a rectangle. So, the distance moved to make one complete round of field will be equal to its perimeter.

So, Distance covered in 1 round = Perimeter of a rectangular field

$p = 2( l+ b)$

By putting the values, we get

$p = 2(80 + 60)$

$p = 2 \times 140$

$p = 280m$

Now, the distance moved by the boy in 10 rounds = distance moved in 1 round x 10

$total \: distance = p \times 10$

$total \: distance =280 \times 10$

$total \: distance =2800m$

Hence, The distance moved by a boy to make one complete round of the field and the distance moved by the same boy to make ten rounds of this field is 280m and 2800m respectively.

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