Question

For a rxn
A+B--2C+2D, Kp=1.2×10^3kPa at 450k.calculate the value of Kc in mol/l.

Answer 1

Hope you find it helpful

Answer 2

Kc and Kp are the equilibrium constant of a gaseous mixture. Kc is molar concentration and Kp is partial pressure of a gas inside a closed system.

For the given reaction,

A+B---2C+2D

Given, Kp=1.2×10³kPa=1.2×10³×10³Pa

                =1.2×10⁶Pa=1.2×10⁶×9.869×10⁻⁶atm=11.8atm

And the temperature, T=450k

R=0.082.6 L atm/mol K

For this reaction, Δn=n₁-n₂=4-2=2

The relation between Kp and Kc is,

Kp=Kc(RT)Δn

⇒11.8=Kc(0.0820×450)²

⇒11.8=Kc(86.927)²

⇒Kc≅0.009 mol/L