Question

For a sequence Sn= 2n(6n+4). Find tn. Examine whether the given sequence is an arithmetic progression.

Answer 1

HEY MATE,

TO FIND THAT THIS IS AN AP WE NEED TO FIND 'A' AND 'D'.

Sn = 2n(6n+4)

S1 = 2(1)(6 X 1 + 4)

S1 = 2(10)

S1 = A1 = 20.

S2 = 2n(6n+4)

S2 = 2(2)(6 X 2 + 4)

S2= 4(16)

S2 = 64

WE KNOW THE FORMULA,

An = Sn - Sn-1

A2 = S2 - S2-1

A2 = S2 - S1

A2 = 64 - 20

A2 = 44.

A1 = 20 , A+D= 44

20 + D = 44

D = 44-20

D = 24.

I HOPE THIS WILL HELP YOU...

PLS MARK AS BRAINLIEST.

Answer 2

TO FIND THAT THIS IS AN AP WE NEED TO FIND 'A' AND 'D'.

Sn = 2n(6n+4)

S1 = 2(1)(6 X 1 + 4)

S1 = 2(10)

S1 = A1 = 20.

S2 = 2n(6n+4)

S2 = 2(2)(6 X 2 + 4)

S2= 4(16)

S2 = 64

WE KNOW THE FORMULA,

An = Sn - Sn-1

A2 = S2 - S2-1

A2 = S2 - S1

A2 = 64 - 20

A2 = 44.

A1 = 20 , A+D= 44

20 + D = 44

D = 44-20

D = 24.A